标签:style class blog code tar color
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4
5 6 7 0 1 2).
You are given a target value to search. If found in the array return its index, otherwise return -1.
You may assume no duplicate exists in the array.
思路:因为是有序序列的变种,可以考虑应用二分查找。有两种分类讨论方式,一种是根据A[middle]与target的值比较进行讨论;一种是根据找出序列中的递增序列然后继续讨论。
代码一:
class Solution {
public:
int search(int A[], int n, int target) {
if(n <= 0) return -1;
int left = 0;
int right = n - 1;
int middle = 0;
while(left <= right)
{
middle = (left + right) / 2;
if(A[middle] == target)
return middle;
else if(A[middle] < target)
{
if(A[left] >= A[middle] && A[right] < target)
right = middle - 1;
else
left = middle + 1;
}
else
{
if(A[right] <= A[middle] && A[left] > target)
left = middle + 1;
else
right = middle - 1;
}
}
return -1;
}
};
class Solution {
public:
int search(int A[], int n, int target) {
if(n <= 0) return -1;
int left = 0;
int right = n - 1;
int middle = 0;
while(left <= right)
{
middle = (left + right) / 2;
if(A[middle] == target)
return middle;
if(A[left] <= A[middle])
{
if(A[left] <= target && target < A[middle])
right = middle - 1;
else
left = middle + 1;
}
else
{
if(A[middle] < target && target <= A[right])
left = middle + 1;
else
right = middle - 1;
}
}
return -1;
}
};【Leetcode】Search in Rotated Sorted Array,布布扣,bubuko.com
【Leetcode】Search in Rotated Sorted Array
标签:style class blog code tar color
原文地址:http://blog.csdn.net/lipantechblog/article/details/34515925