输入代码:
/*
*Copyright (c)2015,烟台大学计算机与控制工程学院
*All rights reserved.
*文件名称:sum123.cpp
*作 者:林海云
*完成日期:2015年6月12日
*版 本 号:v2.0
*
*问题描述:在圆类上重载关系运算符(6种),使之能够按圆的面积比较两个圆的大小。自编main函数完成测试
*程序输入:无
*程序输出:按要求比较两圆面积的大小
*/
#include <iostream>
#include<Cmath>
using namespace std;
class Point
{
public:
Point(double a=0,double b=0):x(a),y(b) {}
protected:
double x,y;
};
class Circle:public Point //circle是Point类的公用派生类
{
public:
Circle(double a=0,double b=0,double r=0): Point(a,b),radius(r) { }
double area ( ) const; //计算圆面积
friend ostream &operator<<(ostream &,const Circle &);
//重载关系运算符运算符,使之能够按圆的面积比较两个圆的大小;
bool operator>(const Circle &);
bool operator<(const Circle &);
bool operator>=(const Circle &);
bool operator<=(const Circle &);
bool operator==(const Circle &);
bool operator!=(const Circle &);
protected:
double radius;
};
//计算圆面积
double Circle::area( ) const
{
return 3.14159*radius*radius;
}
//重载运算符“<<”,使之按规定的形式输出圆的信息
ostream &operator<<(ostream &output,const Circle &c)
{
output<<"Center=["<<c.x<<", "<<c.y<<"], r="<<c.radius;
return output;
}
//重载关系运算符(种)运算符,使之能够按圆的面积比较两个圆的大小;
bool Circle::operator>(const Circle &c)
{
return (this->radius - c.radius) > 1e-7;
}
bool Circle::operator<(const Circle &c)
{
return (c.radius - this->radius) > 1e-7;
}
bool Circle::operator>=(const Circle &c)
{
return !(*this < c);
}
bool Circle::operator<=(const Circle &c)
{
return !(*this > c);
}
bool Circle::operator==(const Circle &c)
{
return abs(this->radius - c.radius) < 1e-7;
}
bool Circle::operator!=(const Circle &c)
{
return abs(this->radius - c.radius) > 1e-7;
}
int main( )
{
Circle c1(3,2,4),c2(4,5,5);
cout<<"圆c1( "<<c1<<" )的面积是 "<<c1.area()<<endl;
cout<<"圆c2( "<<c2<<" )的面积是 "<<c2.area()<<endl;
cout<<"圆c1 ";
if(c1>c2)
cout<<"圆c1大于圆c2."<<endl;
if(c1<c2)
cout<<"圆c1小于圆c2."<<endl;
if(c1>=c2)
cout<<"圆c1大于等于圆c2."<<endl;
if(c1<=c2)
cout<<"圆c1小于等于圆c2."<<endl;
if(c1==c2)
cout<<"圆c1等于圆c2."<<endl;
if(c1!=c2)
cout<<"圆c1不等于圆c2."<<endl;
return 0;
}
原文地址:http://blog.csdn.net/linhaiyun_ytdx/article/details/46475495