标签:save com poj seq esc action inline ext treap
| Time Limit: 1000MS | Memory Limit: 10000KB | 64bit IO Format: %I64d & %I64u |
Description
N Transaction i Black Box contents after transaction Answer
(elements are arranged by non-descending)
1 ADD(3) 0 3
2 GET 1 3 3
3 ADD(1) 1 1, 3
4 GET 2 1, 3 3
5 ADD(-4) 2 -4, 1, 3
6 ADD(2) 2 -4, 1, 2, 3
7 ADD(8) 2 -4, 1, 2, 3, 8
8 ADD(-1000) 2 -1000, -4, 1, 2, 3, 8
9 GET 3 -1000, -4, 1, 2, 3, 8 1
10 GET 4 -1000, -4, 1, 2, 3, 8 2
11 ADD(2) 4 -1000, -4, 1, 2, 2, 3, 8
Input
Output
Sample Input
7 4 3 1 -4 2 8 -1000 2 1 2 6 6
Sample Output
3 3 1 2
Hint
Source
treap套用模板就可以:
#include <iostream>
#include <cstdio>
#include <cstdlib>
using namespace std;
#define maxn 30000+5
int m,n;
int a[maxn],b[maxn];
int val[maxn],ch[maxn][2],r[maxn],size[maxn],root,cnt,counts[maxn];
inline void pushup(int rt)
{
size[rt] = size[ch[rt][0]] + size[ch[rt][1]] + counts[rt];
}
void rotate(int &x,int kind)
{
int y = ch[x][kind^1];
ch[x][kind^1] = ch[y][kind];
ch[y][kind] = x;
pushup(x);
pushup(y);
x = y;
}
void newnode(int &rt, int v)
{
rt = ++ cnt;
val[rt] = v;
ch[rt][0] = ch[rt][1] = 0;
size[rt] = counts[rt] = 1;
r[rt] = rand();
}
void insert(int &rt, int v)
{
if(rt == 0)
{
newnode(rt, v);
return;
}
if(val[rt] == v)
counts[rt] ++;
else
{
int kind = (val[rt] < v);
insert(ch[rt][kind], v);
if(r[ch[rt][kind]] < r[rt])
rotate(rt, kind^1);
}
pushup(rt);
}
int select(int rt,int k)
{
if(size[ch[rt][0]] >= k) return select(ch[rt][0], k);
if(size[ch[rt][0]] + counts[rt] >= k) return val[rt];
return select(ch[rt][1], k - size[ch[rt][0]] - counts[rt]);
}
int main()
{
root = 0;
cnt = 0;
while(scanf("%d%d",&n,&m) != EOF)
{
for(int i = 1;i <= n;i ++)
scanf("%d", &a[i]);
for(int j = 1;j <= m;j ++)
scanf("%d", &b[j]);
int k = 1;
for(int i = 1;i <= n;i ++)
{
insert(root, a[i]);
if(k > n) break;
while(b[k] == i)
{
printf("%d\n",select(root, k));
k ++;
}
}
}
return 0;
}
也能够使用优先队列来做,维护两个优先队列~
#include <iostream>
#include <cstdio>
#include <queue>
#include <vector>
using namespace std;
#define maxn 30000 + 5
int main()
{
int n, m;
priority_queue<int, vector<int>, greater<int> > q1;
priority_queue<int, vector<int>, less<int> > q2;
int a[maxn],b[maxn];
while(scanf("%d%d",&n, &m) != EOF)
{
while(!q1.empty())
q1.pop();
while(!q2.empty())
q2.pop();
for(int i = 1;i <= n;i ++)
{
scanf("%d", &a[i]);
}
for(int j = 1;j <= m;j ++)
{
scanf("%d", &b[j]);
}
int k = 1;
for(int i = 1;i <= n;i ++)
{
if(!q1.empty())
{
if(a[i] < q1.top())
q2.push(a[i]);
else
{
q2.push(q1.top());
q1.pop();
q1.push(a[i]);
}
}
else q2.push(a[i]);
while(b[k] == i)
{
if(q2.size() == k)
{
printf("%d\n",q2.top());
}
else if(q2.size() > k)
{
while(q2.size() != k)
{
q1.push(q2.top());
q2.pop();
}
printf("%d\n",q2.top());
}
else if(q2.size() < k)
{
while(q2.size() != k)
{
q2.push(q1.top());
q1.pop();
}
printf("%d\n",q2.top());
}
k++;
}
}
}
return 0;
}
标签:save com poj seq esc action inline ext treap
原文地址:http://www.cnblogs.com/jzdwajue/p/6897910.html