码迷,mamicode.com
首页 > 其他好文 > 详细

Codeforces Round #604 (Div. 2) A. Beautiful String

时间:2019-12-07 01:04:48      阅读:147      评论:0      收藏:0      [点我收藏+]

标签:space   pac   wan   aaa   com   codeforce   代码   std   ORC   

链接:

https://codeforces.com/contest/1265/problem/A

题意:

A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.

Ahcl wants to construct a beautiful string. He has a string s, consisting of only characters ‘a‘, ‘b‘, ‘c‘ and ‘?‘. Ahcl needs to replace each character ‘?‘ with one of the three characters ‘a‘, ‘b‘ or ‘c‘, such that the resulting string is beautiful. Please help him!

More formally, after replacing all characters ‘?‘, the condition si≠si+1 should be satisfied for all 1≤i≤|s|?1, where |s| is the length of the string s.

思路:

直接暴力枚举,判断一遍

代码:

#include<bits/stdc++.h>
using namespace std;
 
string s;
 
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0), cout.tie(0);
    int t;
    cin >> t;
    while(t--)
    {
        cin >> s;
        bool flag = true;
        for (int i = 0;i < s.length();i++)
        {
            if (s[i] == '?')
            {
                int t = -1;
                for (int j = 0;j < 3;j++)
                {
                    if ((i-1 < 0 || s[i-1] != (char)('a'+j)) && (i+1 >= s.length() || s[i+1] != (char)('a'+j)))
                    {
                        t = j;
                        break;
                    }
                }
                s[i] = (char)('a'+t);
            }
        }
        for (int i = 1;i < s.length();i++)
        {
            if (s[i] == s[i-1])
                flag = false;
        }
        cout << (flag ? s : "-1") << endl;
    }
 
    return 0;
}

Codeforces Round #604 (Div. 2) A. Beautiful String

标签:space   pac   wan   aaa   com   codeforce   代码   std   ORC   

原文地址:https://www.cnblogs.com/YDDDD/p/12000238.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!