标签:class code java http tar com
The n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other.

Given an integer n, return all distinct solutions to the n-queens puzzle.
Each solution contains a distinct board configuration of the n-queens‘ placement, where‘Q‘and‘.‘both indicate a queen and an empty space respectively.
For example,
There exist two distinct solutions to the 4-queens puzzle:
[ [".Q..", // Solution 1 "...Q", "Q...", "..Q."], ["..Q.", // Solution 2 "Q...", "...Q", ".Q.."] ]
https://oj.leetcode.com/problems/n-queens/
思 路:经典的8皇后问题,还是老思路,生成perm数组,perm[i]的只代表第i行放置皇后的列数,递归下去的条件是不冲突(冲突的情 况:perm[j] == i || perm[j] - j == i - cur || perm[j] + j == i + cur),然后根据题目要求生成结果的形式即可。
import java.util.ArrayList;
public class Solution {
public ArrayList<String[]> solveNQueens(int n) {
if (n <= 0)
return null;
ArrayList<String[]> res = new ArrayList<String[]>();
int[] perm = new int[n];
slove(perm, 0, n, res);
return res;
}
private void slove(int[] perm, int cur, int n, ArrayList<String[]> res) {
if (cur == n) {
String[] tmp = new String[n];
for (int i = 0; i < n; i++) {
char[] item = new char[n];
for (int j = 0; j < n; j++)
item[j] = ‘.‘;
item[perm[i]] = ‘Q‘;
tmp[i] = new String(item);
}
// System.out.println(Arrays.toString(tmp));
res.add(tmp);
} else {
int i;
for (i = 0; i < n; i++) {
int j;
boolean ok = true;
for (j = 0; j < cur; j++) {
if (perm[j] == i || perm[j] - j == i - cur
|| perm[j] + j == i + cur)
ok = false;
}
if (ok) {
perm[cur] = i;
slove(perm, cur + 1, n, res);
}
}
}
}
public static void main(String[] args) {
System.out.println(new Solution().solveNQueens(4));
}
}
[leetcode] N-Queens,布布扣,bubuko.com
标签:class code java http tar com
原文地址:http://www.cnblogs.com/jdflyfly/p/3810760.html